chemistry lab test

2 e groups
0 lone pairs
e pair geometry: linear
molecular geometry: linear
bond angles: 180
3 e groups
0 lone pairs
e pair geometry: trigonal planar
molecular geometry: trigonal planar
bond angles: 120
3 e groups
1 electron pair
e pair geometry: trigonal planar
molecular geometry: bent
bond angles: 120
4 e groups
0 lone pairs
e pair geometry: tetrahedral
molecular geometry: tetrahedral
bond angles: 109.5
4 e groups
1 lone pair
e pair geometry: tetrahedral
molecular geometry: trigonal pyramid
bond angles: 109.5
4 e groups
2 lone pairs
e pair geometry: tetrahedral
molecular geometry: bent
bond angles: 109.5
5 e groups
0 lone pairs
e pair geometry: trigonal bipyramidal
molecular geometry: trigonal bi pyramidal
bond angles: 90,120,180
5 e groups
1 lone pair
e pair geometry: trigonal bipyramidal
molecular geometry: seesaw
bond angles: 90, 120, 180
5 e groups
2 lone pairs
e pair geometry: trigonal bipyramidal
molecular geometry: T shaped
bond angles: 90, 180
5 e groups
3 lone pairs
e pair geometry: trigonal bipyramidal
molecular geometry: linear
bond angles: 180
6 e groups
0 lone pairs
e pair geometry: octahedral
molecular geometry: octahedral
bond angles: 90
6 e groups
1 lone pair
e pair geometry: octahedral
molecular geometry: square pyramidal
bond angles: 90
6 e groups
2 lone pairs
e pair geometry: octahedral
molecular geometry: square planar
bond angles: 90
molality
moles of solute/mass of solvent(kg)
molarity
moles of solute/liters of solution
freezing point depression formula
delta T = i x Kf x m
i = vant hoff factor
Kf = freezing point depression constant
m = molality
Rate Law
Rate = k [A]^m [B]^n
k = rate constant
[A] & [B] = molar concentration of reactants
m & n = order of the reactants
order of the reaction
the sum of the orders = m+n
Mass percent
= (mass of solute/total mass of solution)x 100
Dilution calculation
Mi x Vi = Mf X Vf
ideal gas law
PV = nRT
R = .08206
Arrhenius Equation
k = Ae^(-Ea/RT)
R = 8.31447 J/(mol * K)
Arrhenius equation when comparing two points
ln (k2/k1) = (Ea/R){(1/T1) – (1/T2)}
R = 8.31447 J/(mol * K)
y = mx + b for Arrhenius Equation
ln k = (-Ea/R)(1/T) + ln A
y = m x + b
M/s =
(P/s)/RT
what is the equilibrium constant for:
Fe+3 + SCN- -> FeSCN+2
Kc = (FeSCN+2)/ (Fe+3)(SCN-)
(FeSCN+2)eq
____________ = _____
(FeSCN+2)std
Aeq
_____
Astd
(Fe3+)eq =
(Fe3+)i – (FeSCN2+)eq
(SCN-)eq =
(SCN-)i – (FeSCN2+)eq
standard deviation of 143, 157, 137, 145
avg = 146
8.41
Write the solubility product expression for the dissolution of Ca(OH)2
ksp = (Ca2+)(OH-)^2
pH=
pKa + log (base)/(acid)